Write a function that takes a character (i.e. a string of length 1) and returns True if it is a vowel, False otherwise| Python practical

 In the English language, there are five vowels: A, E, I, O, and U. Sometimes, Y is also considered a vowel. A vowel is a speech sound in which the vocal cords vibrate, causing air to flow through the mouth.

In this blog post, we will discuss how to write a Python function that takes a character (i.e. a string of length 1) and returns True if it is a vowel, False otherwise.

To start, we need to define the function. We will call our function is_vowel, and it will take one argument, which is the character we want to check. Here's the code to define our function:

def is_vowel(char):

    pass

Now that we have defined our function, we can write the logic to determine if the character is a vowel or not. We can do this by checking if the character is one of the vowels (A, E, I, O, or U). We can also check if it is Y, but only if it is not the first letter in a word.

def is_vowel(char):

    vowels = ['a', 'e', 'i', 'o', 'u']

    if char.lower() in vowels:

        return True

    elif char.lower() == 'y' and char not in ['Y', 'y']:

        return True

    else:

        return False

Let's break down this code. We first define a list of vowels, which are all in lowercase. We then check if the lowercase version of the character is in the list of vowels. If it is, we return True. If it is not, we check if the character is Y and is not the first letter in a word (i.e., it is not capitalized). If it is, we return True. If it is not, we return False.

Now that we have our function, let's test it with some sample inputs:

print(is_vowel('a')) # True

print(is_vowel('b')) # False

print(is_vowel('E')) # True

print(is_vowel('x')) # False

print(is_vowel('y')) # True

print(is_vowel('Y')) # False

As expected, our function returns True for vowels and False for non-vowels. It also correctly handles Y as a vowel or a consonant, depending on its position in the word.

In conclusion, we have successfully written a Python function that takes a character and determines if it is a vowel or not. This function can be useful in various applications, such as text processing and natural language processing.

Complete code :- 

def find_vowel(s):

    l=['a','e','i','o','u']

    for i in s:

        if i in l:

            print('True')

        else:

            print('False')